Class 12 Statistics Notes · GSEB
Second Order Derivative
Second Order Derivative — learn f'(x), concavity, and the second derivative test for maxima and minima. GSEB Class 12 Commerce Statistics notes with an interactive concavity explorer.
Last updated: 24 Sep 2026
Notes
What Is a Second Order Derivative?
If f′(x) is the speedometer, f″(x) is the accelerator pedal: it tells you whether the rate itself is rising or falling. Its biggest exam use is the maximum–minimum test.
f″(x)
prime-prime
d²y/dx²
Leibniz form
ÿ
dot form
f⁽²⁾(x)
superscript form
It is a derivative of a derivative
Concavity: What f″ Tells You Geometrically
The sign of f″ decides which way the curve bends. Drag the point along y = x³ − 3x and watch the colour change.
f′(x) = 3x² − 3
1.32
f″(x) = 6x
7.20
Concavity
Bowl up (∪)
Read the colour flip
f″ > 0 — concave up
Curve bowls upward like a cup. At a stationary point → minimum.
f″ < 0 — concave down
Curve caps over like an umbrella. At a stationary point → maximum.
f″ = 0 — possible inflection
Concavity may flip here. Alone it proves nothing — check the sign change around it.
Why businesses care about concavity
Explore: Second Derivative Solver
Enter any polynomial and step through the full f″ workflow: differentiate → differentiate again → evaluate concavity at a slideable point → locate the inflection points. The curve is colour-coded by the sign of f″ as soon as step 2 unlocks.
Work through steps 1–4: differentiate → differentiate again → evaluate f″ where you slide → locate the inflection points.
How to read the graph
The Max–Min Test
Combined with f′ = 0, the sign of f″ decides whether a stationary point is a peak or a valley.
| Condition at x = a | Verdict | Shape |
|---|---|---|
| f′(a) = 0 and f″(a) < 0 | Maximum | peak — bowl down |
| f′(a) = 0 and f″(a) > 0 | Minimum | valley — bowl up |
| f′(a) = 0 and f″(a) = 0 | Inconclusive | use the first derivative test |
f″ = 0 is not an answer
Worked Examples
Solved Example
Problem
Solution
d²y/dx² at x = 1 is 26
Solved Example
Problem
Solution
x = 2
Solved Example
Problem
Solution
f″(x) = −(3/16) x^(−7/4)
Key Takeaways
Key Takeaways
- ★ f″(x) = d/dx [f′(x)] — differentiate the derivative; never square the first derivative.
- f″ > 0 → concave up (bowl ∪) · f″ < 0 → concave down (bowl ∩) · f″ = 0 → check for an inflection point.
- ★ Max–min test: f′ = 0 with f″ < 0 gives a maximum; f′ = 0 with f″ > 0 gives a minimum.
- If f″ = 0 the test is inconclusive — fall back to the sign of f′ around the point.
- So what? Cost minimisation, revenue maximisation and profit maximisation in the business topics are literally this test with rupee-shaped curves.