Class 12 Statistics Notes · GSEB
Standard Forms
Standard Forms — use direct substitution for polynomial limits and the key formula (xⁿ − aⁿ)/(x − a) → n·aⁿ⁻¹ to resolve 0/0 forms quickly. GSEB Class 12 Commerce Statistics notes with step-by-step factorisations.
Last updated: 23 Sep 2026
Notes
What Are Standard Forms?
Standard Form 1 — Polynomials (Direct Substitution)
Just plug in
Any expression built from +, −, × and whole-number powers is a polynomial — substitute without hesitation.
Examples (all direct substitution):
lim(x→2) (3x² − 5x + 1) = 12 − 10 + 1 = 3
lim(x→−1) (x³ + 4x) = −1 − 4 = −5
lim(x→0) (7) = 7 (constant polynomial)
When is something NOT a polynomial?
Standard Form 2 — The Key Formula
Substituting into (xⁿ − aⁿ)/(x − a) always gives 0/0. Instead of factoring from scratch each time, memorise this result — it is the single most examined limit pattern in this chapter.
Left side pattern:
numerator = xⁿ − aⁿ (difference of like powers)
denominator = x − a (single linear factor)
Right side recipe:
write the power n, multiply by aⁿ⁻¹
e.g. n = 3, a = 2 → 3 × 2² = 12
n = 2 special case
Factor (x − a)(x + a), cancel, substitute x = a into (x + a) → 2a. E.g. a = 4 → answer 8.
n = 3 special case
Factor (x − a)(x² + ax + a²), cancel, substitute → 3a². E.g. a = 2 → 3 × 4 = 12.
Dress code
Explore: Standard Form Lab
Drag n and a. The lab shows why naive substitution fails and how n·aⁿ⁻¹ rescues the answer every single time.
Evaluate
lim(x→3) (x² − 3²)/(x − 3)
Naive plug-in
0/0
Formula n · aⁿ⁻¹
2 × 3^1
Answer
6
How the formula was born
The 0/0 Rescue Flow
Substitution gives 0/0? Run this three-step rescue: factor → cancel → substitute.
Step 0 — Direct substitution (the trap)
(x⁴ − 16)/(x − 2) at x = 2 → 2^4 − 2^4 = 0 over 0 → 0/0, blocked
Step 1 — Factorise out (x − 2)
numerator = (x − 2)·(x^3 + x^2·2 + … + 2^3)
Step 2 — Cancel (x − 2) for x ≠ 2
→ (x^3 + x^2·2 + … + 2^3) — the dangerous factor is gone
Step 3 — Substitute x = 2 safely
2^3 + 2^3 + … (4 terms of 2^3) = 4·2^3 = 32
Is f(x) a polynomial?
Does substitution give 0/0?
Is it (xⁿ − aⁿ)/(x − a)?
Solved Examples
Solved Example
Problem
Solution
6
Solved Example
Problem
Solution
12
Solved Example
Problem
Solution
8
Solved Example
Problem
Solution
10
Key Takeaways
Key Takeaways
- Polynomial? Plug in directly: lim(x→a) P(x) = P(a).
- ★ Key formula: lim(x→a) (xⁿ − aⁿ)/(x − a) = n·aⁿ⁻¹ — one-line answers for difference-of-powers 0/0.
- Know the special cases cold: (x² − a²)/(x − a) → 2a and (x³ − a³)/(x − a) → 3a².
- Check the dress code: denominator (x − a) and numerator xⁿ − aⁿ with matching a — otherwise factor manually.
- Exam order: polynomial → plug in · 0/0 → factor/cancel · key-formula shape → n·aⁿ⁻¹ instantly.